Colonel William A. Phillips

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The 1908 United States presidential election in Rhode Island took place on November 3, 1908 as part of the 1908 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Rhode Island voted for the Republican nominees, Secretary of War William Howard Taft of Ohio and his running mate James S. Sherman of New York. They defeated the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate John W. Kern of Indiana. Taft won the state by a margin of 26.6%.

With 60.76% of the popular vote, Rhode Island would be Taft's fifth strongest victory in terms of percentage in the popular vote after Vermont, Maine, Michigan and North Dakota.[1]

Bryan had previously lost Rhode Island to William McKinley in both 1896 and 1900.

Results

1908 United States presidential election in Rhode Island[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican William Howard Taft of Ohio James Schoolcraft Sherman of New York 43,942 60.76% 4 100.00%
Democratic William Jennings Bryan of Nebraska John Worth Kern of Indiana 24,706 34.16% 0 0.00%
Socialist Eugene Victor Debs of Indiana Benjamin Hanford of New York 1,365 1.89% 0 0.00%
Independence Thomas Louis Hisgen of Massachusetts John Temple Graves of Georgia 1,105 1.53% 0 0.00%
Prohibition Eugene Wilder Chafin of Illinois Aaron Sherman Watkins of Ohio 1,016 1.40% 0 0.00%
Socialist Labor August Gillhaus of New York Donald L. Munro of Virginia 183 0.25% 0 0.00%
Total 72,317 100.00% 4 100.00%

See also

References

  1. ^ "1908 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. ^ "1908 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved December 23, 2013.