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| Elections in Alabama |
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 Government |
The 1884 United States presidential election in Alabama took place on November 4, 1884, as part of the nationwide presidential election. Alabama voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president.[2]
Alabama was won by Grover Cleveland, the 28th governor of New York, (D–New York), running with the former governor of Indiana Thomas A. Hendricks, with 60.37% of the popular vote, against Secretary of State James G. Blaine (R-Maine), running with Senator John A. Logan, with 38.69% of the vote.[2]
Results
| 1884 United States presidential election in Alabama[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Grover Cleveland of New York | Thomas A. Hendricks of Indiana | 92,736 | 60.37% | 10 | 100.00% | ||
| Republican | James G. Blaine of Maine | John A. Logan of Illinois | 59,444 | 38.69% | 0 | 0.00% | ||
| Greenback | Benjamin Butler of Massachusetts | Absolom M. West of Mississippi | 762 | 0.50% | 0 | 0.00% | ||
| Prohibition | John St. John of Kansas | William Daniel of Maryland | 610 | 0.40% | 0 | 0.00% | ||
| Write-in | Write-in of United States | Write-in of United States | 72 | 0.05% | 0 | 0.00% | ||
| Total | 153,624 | 100.00% | 10 | 100.00% | ||||
See also
References
