| Elections in Kentucky |
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 Government |
The 1856 United States presidential election in Kentucky took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for president and vice president.
Kentucky voted for the Democratic candidate, James Buchanan, over American Party candidate Millard Fillmore. Buchanan won Kentucky by a margin of 5.08%.
Republican Party candidate John C. Frémont was not on the ballot in the state.
Results
| United States presidential election in Kentucky, 1856[1][2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | James Buchanan of Pennsylvania | John C. Breckinridge of Kentucky | 74,642 | 52.54% | 12 | 100.00% | ||
| Know Nothing | Millard Fillmore of New York | Andrew Jackson Donelson of Tennessee | 67,416 | 47.46% | 0 | 0.00% | ||
| Total | 142,058 | 100.00% | 12 | 100.00% | ||||
References
- ^ "1856 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved December 3, 2017.
- ^ "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 3, 2017.
