| Elections in Delaware |
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The 1960 United States presidential election in Delaware took place on November 8, 1960, as part of the 1960 United States presidential election. State voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Delaware was won by Senator John F. Kennedy (D–Massachusetts), running with Senator Lyndon B. Johnson, with 50.63% of the popular vote against incumbent Vice President Richard Nixon (R–California), running with United States Ambassador to the United Nations Henry Cabot Lodge Jr., with 49.00% of the popular vote.[3][4]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | John F. Kennedy | 99,590 | 50.63% | |
| Republican | Richard Nixon | 96,373 | 49.00% | |
| Write-in | 720 | 0.37% | ||
| Total votes | 196,683 | 100.00% | ||
See also
References
- ^ "United States Presidential election of 1960 - Encyclopædia Britannica". Retrieved June 7, 2017.
- ^ "1960 Election for the Forty-Fourth Term (1961-65)". Retrieved June 7, 2017.
- ^ "1960 Presidential General Election Results - Delaware". Retrieved June 7, 2017.
- ^ "The American Presidency Project - Election of 1960". Retrieved June 7, 2017.
