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The 1848 United States presidential election in Wisconsin was held on November 7, 1848, as part of the 1848 United States presidential election. It was the first presidential election held in Wisconsin since its admission to the Union on May 29, earlier the same year. Democratic candidate Lewis Cass won the state with 38% of the vote, carrying the state's 4 electoral votes.

With 26.6% of the popular vote, Wisconsin would prove to be Van Buren's third strongest state after Vermont and Massachusetts.[1]

The 1848 election began a trend in Wisconsin where the state would vote the same as neighboring Iowa, as the two states have voted in lockstep with each other on all but 6 occasions - 1892, 1924, 1940, 1976, 2004, and 2020. This was the last time until 1988 that Wisconsin would back a losing Democrat in a presidential election.

Results

1848 United States presidential election in Wisconsin[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Lewis Cass of Michigan William O. Butler of Kentucky 15,001 38.30% 4 100.00%
Whig Zachary Taylor of Louisiana Millard Fillmore of New York 13,747 35.10% 0 0.00%
Free Soil Martin Van Buren of New York Charles Francis Adams, Sr. of Massachusetts 10,418 26.60% 0 0.00%
Total 39,166 100.00% 4 100.00%

See also

References

  1. ^ "1848 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. ^ "1848 Presidential General Election Results - Wisconsin". Retrieved May 10, 2016.