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The 1996 United States presidential election in Hawaii took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College, who voted for president and vice president.

Hawaii was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 56.93% to 31.64% by a margin of 25.29%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third, with 7.6% of the popular vote.^[1]

Results

1996 United States presidential election in Hawaii
Party		Candidate	Running mate	Votes	Percentage	Electoral votes
	Democratic	Bill Clinton (incumbent)	Al Gore	205,012	56.93%	4
	Republican	Bob Dole	Jack Kemp	113,943	31.64%	0
	Reform	Ross Perot	Pat Choate	27,358	7.60%	0
	Green	Ralph Nader	Winona LaDuke	10,386	2.88%	0
	Libertarian	Harry Browne	Jo Jorgensen	2,493	0.69%	0
	Natural Law	Dr. John Hagelin	Dr. V. Tompkins	570	0.16%	0
	U.S. Taxpayers' Party	Howard Phillips	Herbert Titus	358	0.10%	0
Totals				360,120	100.0%	4

County	Bill Clinton Democratic		Bob Dole Republican		Various candidates Other parties		Margin		Total votes cast
County	#	%	#	%	#	%	#	%	Total votes cast
Hawaii	27,262	55.66%	13,516	27.60%	8,199	16.74%	13,746	28.06%	48,977
Honolulu	143,793	56.33%	85,779	33.61%	25,684	10.06%	58,014	22.72%	255,256
Kalawao	46	73.02%	13	20.63%	4	6.35%	33	52.39%	63
Kauai	13,357	63.54%	5,325	25.33%	2,338	11.13%	8,032	38.21%	21,020
Maui	20,600	59.08%	9,323	26.74%	4,944	14.18%	11,277	32.34%	34,867
Totals	205,012	56.93%	113,943	30.04%	41,165	11.43%	91,069	25.29%	360,120

^ Leip, David. "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved June 14, 2018.