Comobabi is both a census-designated place (CDP) and a populated place in Pima County, Arizona, United States. The population was 8 at the 2010 census. It is located within the Tohono O'odham Indian Reservation.
Geography
Comobabi is located at 32°03′14″N 111°48′10″W / 32.05389°N 111.80278°W (32.053847, −111.802885). According to the United States Geological Survey, the CDP has a total area of 1.15 square miles (3.0 km2), all land.[2]
Demographics
| Census | Pop. | Note | %± |
|---|---|---|---|
| 2020 | 44 | — | |
| U.S. Decennial Census[3] | |||
As of the 2010 census, there were 8 people living in the CDP: 4 male and 4 female. 1 was 19 years old or younger, 1 was ages 20–34, 1 was between the ages of 35 and 49, 4 were between 50 and 64, and the remaining 1 was aged 65 and above. The median age was 53.0 years.
The racial makeup of the CDP was 100% Native American. 0% of the population were Hispanic or Latino of any race.
There were 3 households in the CDP, 2 family households (66.7%) and 1 non-family households (33.3%), with an average household size of 2.67. Of the family households, there were 1 married couples living together, and 1 single mothers.
The CDP contained 5 housing units, of which 3 were occupied and 2 were vacant.[4]
References
- ^ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved October 29, 2021.
- ^ a b "Feature Detail Report for: Comobabi Census Designated Place". Geographic Names Information System. United States Geological Survey, United States Department of the Interior.
- ^ "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.
- ^ "American FactFinder: Comobabi CDP, Arizona". United States Census Bureau. Archived from the original on February 13, 2020. Retrieved November 4, 2016.
